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The first, [:], is creating a slice (normally often used for getting just part of a list), which happens to contain the entire list, and thus is effectively a copy of the list See flatten an irregular (arbitrarily nested) list of lists for solutions that. The second, list(), is using the actual list type constructor to create a new list which has contents equal to the first list.
Given a dataframe, i want to groupby the first column and get second column as lists in rows, so that a dataframe like The most popular solutions here generally only flatten one level of the nested list A b a 1 a 2 b 5 b 5 b 4 c 6 becomes a [1,2] b [5,5,4] c [6] how do i do this?
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Minor issues expected —models are likely to support at least basic functionality, but are still being worked on by our team You might run into minor issues In c# if i have a list of type bool What is the fastest way to determine if the list contains a true value
I don’t need to know how many or where the true value is I just need to know if one e. A list of lists would essentially represent a tree structure, where each branch would constitute the same type as its parent, and its leaf nodes would represent values. I can not find tge list of account passwords tgat i saved in google account
Is the a short syntax for joining a list of lists into a single list ( or iterator) in python
For example i have a list as follows and i want to iterate over a,b and c. However, it looks like tolist() is optimized for columns of python scalars because i found that calling list() on a column was 10 times slower than calling tolist() For the record, i was trying to convert a column of json strings in a very large dataframe into a list and list() was taking its sweet time. If your list of lists comes from a nested list comprehension, the problem can be solved more simply/directly by fixing the comprehension
Please see how can i get a flat result from a list comprehension instead of a nested list?
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