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Slope m=0 and intercept at x=0, y=3 this equation can be written, rearranging it, as y=3 Algebra forms of linear equations equations of perpendicular lines This represents an horizontal line (slope zero) passing through y=3 on the y axis.

How do you find the slope of the line passing through (9, 9) and (9, − 4) How do you find the slope that is perpendicular to the line −25 + 8x = 5y We first need to find the slope of the line

Slope = 4, y intercept = 4 the y intercept is the value of y where the function you're plotting crosses the y axis, so if we set x = 0 in the equation we can see we get y = 4

The slope represents the change in y for a unit change in x, and might also be called the gradient of a line It gives us a measure of how steep the line is. Moreover, the values of coefficients and constant in the 2nd equations are 1.5 times of the values of coefficients and constant the first equation. Slope is calculated as the change in y over the change is x (you may have heard of this referred to as rise over run)

So essentially, how fast is the graph increasing or decreasing? Parallel lines have equal slope The slope of line 6x −7y = 10 or 7y = 6x − 10 or y = 6 7 x − 10 7 ∴ slope = 6 7 Hence the slope of the line is also 6 7 [ans]

\qquad \qquad slope of line between \ ( 1, 2 ) \quad and \quad ( 2, 5 ) \ = \ 3 \

# recall the definition of the slope of a line between two points Pv = nrt p is pressure v is volume n is number of moles r is ideal gas constant t is the absolute temperature for an isothermal process, the right hand side of the ideal gas equation does not change Which means pv = constant the slope at any point is given by dp dv = − p v using implicit differentiation or any other methods For adiabatic processes, the path would.

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